Molar Mass of C3H4N2 (Imidazole)

Molar Mass Calculator

What is the molar mass of C₃H₄N₂?

Answer

M(C₃H₄N₂) =

68.079 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	3	12.011	36.033 w ≈ 52.93%	≈ 52.93%
Hhydrogen	4	1.0080	4.0320 w ≈ 5.92%	≈ 5.92%
Nnitrogen	2	14.007	28.014 w ≈ 41.15%	≈ 41.15%
Σ = 68.079 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 52.93%N 41.15%

H 5.92%

Related Calculations

See Also

Liters to Kilograms - How many kilograms are in a liter of water, honey, gasoline, sand and other substances — by density
Grams to Kg - Convert Grams to Kilograms
Percentage Calculator: Fraction to Percent - What percentage one number is of another? Convert fraction into a percentage
Scientific Calculator with Memory & History - Free Engineering Calculator Online with Memory Function, Operation History, Logarithms & Trigonometry. Similar to ti-83, ti-84, ti-89

Recalculate with different values ↑

Molar masses of substances nearby

Formula	M, g/mol
Zn (zinc)	65.38
HCOONa (sodium formate)	68.007
C₃O₂ (carbon suboxide)	68.031
C₃H₄N₂ (imidazole)	68.079
(NH₄)₂S (ammonium sulfide)	68.14
LiNO₃ (lithium nitrate)	68.94
NaNO₂ (sodium nitrite)	68.995

FAQ

What is the molar mass of C3H4N2?

M(C₃H₄N₂) = 68.079 g/mol

How to calculate the molar mass of C₃H₄N₂?

Add up the atomic weights of all the atoms in the formula: 3 × 12.011 + 4 × 1.0080 + 2 × 14.007 = 68.079 g/mol.

How many grams are in 2 moles of C₃H₄N₂?

m = n × M = 2 mol × 68.079 g/mol = 136.158 g.

See Also