Molar Mass of C18H34O2 (Oleic Acid)

Molar Mass Calculator

What is the molar mass of C₁₈H₃₄O₂?

Answer

M(C₁₈H₃₄O₂) =

282.468 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	18	12.011	216.198 w ≈ 76.54%	≈ 76.54%
Hhydrogen	34	1.0080	34.2720 w ≈ 12.13%	≈ 12.13%
Ooxygen	2	15.999	31.998 w ≈ 11.33%	≈ 11.33%
Σ = 282.468 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 76.54%

H 12.13%O 11.33%

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Molar masses of substances nearby

Formula	M, g/mol
FeSO₄·7H₂O (ferrous sulfate heptahydrate)	278.01
PbCl₂ (lead chloride)	278.1
MgI₂ (magnesium iodide)	278.11
C₁₈H₃₄O₂ (oleic acid)	282.468
P₄O₁₀ (phosphorus pentoxide)	283.886
FeH₈N₂O₈S₂ (ferrous ammonium sulfate)	284.04
C₁₈H₃₆O₂ (stearic acid)	284.484

FAQ

What is the molar mass of C18H34O2?

M(C₁₈H₃₄O₂) = 282.468 g/mol

How to calculate the molar mass of C₁₈H₃₄O₂?

Add up the atomic weights of all the atoms in the formula: 18 × 12.011 + 34 × 1.0080 + 2 × 15.999 = 282.468 g/mol.

How many grams are in 2 moles of C₁₈H₃₄O₂?

m = n × M = 2 mol × 282.468 g/mol = 564.936 g.

See Also