Molar Mass of BaCO3 (Barium Carbonate)

Molar Mass Calculator

What is the molar mass of BaCO₃?

Answer

M(BaCO₃) ≈

197.34 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ba: 137.33.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Babarium	1	137.33	137.33 w ≈ 69.59%	≈ 69.59%
Ccarbon	1	12.011	12.011 w ≈ 6.09%	≈ 6.09%
Ooxygen	3	15.999	47.997 w ≈ 24.32%	≈ 24.32%
Σ = 197.338 ≈ 197.34 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Ba 69.59%

O 24.32%C 6.09%

Related Calculations

See Also

Liters to Kilograms - How many kilograms are in a liter of water, honey, gasoline, sand and other substances — by density
Grams to Kg - Convert Grams to Kilograms
Percentage Calculator: Fraction to Percent - What percentage one number is of another? Convert fraction into a percentage
Scientific Calculator with Memory & History - Free Engineering Calculator Online with Memory Function, Operation History, Logarithms & Trigonometry. Similar to ti-83, ti-84, ti-89

Recalculate with different values ↑

Molar masses of substances nearby

Formula	M, g/mol
Pt (platinum)	195.08
C₆H₁₂O₇ (D-gluconic acid)	196.155
Au (gold)	196.97
BaCO₃ (barium carbonate)	197.34
As₂O₃ (arsenic trioxide)	197.841
NaC₆H₇O₆ (sodium ascorbate)	198.106
CaBr₂ (calcium bromide)	199.886

FAQ

What is the molar mass of BaCO3?

M(BaCO₃) ≈ 197.34 g/mol

How to calculate the molar mass of BaCO₃?

Add up the atomic weights of all the atoms in the formula: 137.33 + 12.011 + 3 × 15.999 = 197.338 ≈ 197.34 g/mol.

How many grams are in 2 moles of BaCO₃?

m = n × M = 2 mol × 197.34 g/mol = 394.68 g.

See Also