Molar Mass of BaBr2 (Barium Bromide)

Molar Mass Calculator

What is the molar mass of BaBr₂?

Answer

M(BaBr₂) ≈

297.14 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ba: 137.33.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Babarium	1	137.33	137.33 w ≈ 46.22%	≈ 46.22%
Brbromine	2	79.904	159.808 w ≈ 53.78%	≈ 53.78%
Σ = 297.138 ≈ 297.14 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Br 53.78%Ba 46.22%

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Molar masses of substances nearby

Formula	M, g/mol
CaI₂ (calcium iodide)	293.88
K₂Cr₂O₇ (potassium dichromate)	294.181
HgSO₄ (mercuric sulfate)	296.65
BaBr₂ (barium bromide)	297.14
SbCl₅ (antimony pentachloride)	299.01
C₁₅H₁₀O₇ (quercetin)	302.238
PbSO₄ (lead sulfate)	303.3

FAQ

What is the molar mass of BaBr2?

M(BaBr₂) ≈ 297.14 g/mol

How to calculate the molar mass of BaBr₂?

Add up the atomic weights of all the atoms in the formula: 137.33 + 2 × 79.904 = 297.138 ≈ 297.14 g/mol.

How many grams are in 2 moles of BaBr₂?

m = n × M = 2 mol × 297.14 g/mol = 594.28 g.

See Also