Molar Mass of Ba(OH)2 (Barium Hydroxide)

Molar Mass Calculator

What is the molar mass of Ba(OH)₂?

Answer

M(Ba(OH)₂) ≈

171.34 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ba: 137.33.

Ba(OH)₂ = Ba + 2 × (O + H) → Ba 1, O 2, H 2

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Babarium	1	137.33	137.33 w ≈ 80.15%	≈ 80.15%
Ooxygen	2	15.999	31.998 w ≈ 18.67%	≈ 18.67%
Hhydrogen	2	1.0080	2.0160 w ≈ 1.18%	≈ 1.18%
Σ = 171.344 ≈ 171.34 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Ba 80.15%

O 18.67%H 1.18%

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Molar masses of substances nearby

Formula	M, g/mol
BaO₂ (barium peroxide)	169.33
BaS (barium sulfide)	169.39
AgNO₃ (silver nitrate)	169.87
Ba(OH)₂ (barium hydroxide)	171.34
CeO₂ (cerium(IV) oxide)	172.12
CaSO₄·2H₂O (calcium sulfate dihydrate)	172.16
Yb (ytterbium)	173.05

FAQ

What is the molar mass of Ba(OH)2?

M(Ba(OH)₂) ≈ 171.34 g/mol

How to calculate the molar mass of Ba(OH)₂?

Add up the atomic weights of all the atoms in the formula: 137.33 + 2 × 15.999 + 2 × 1.0080 = 171.344 ≈ 171.34 g/mol.

How many grams are in 2 moles of Ba(OH)₂?

m = n × M = 2 mol × 171.34 g/mol = 342.68 g.

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