Molar Mass of AgNO3 (Silver Nitrate)

Molar Mass Calculator

What is the molar mass of AgNO₃?

Answer

M(AgNO₃) ≈

169.87 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ag: 107.87.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Agsilver	1	107.87	107.87 w ≈ 63.50%	≈ 63.50%
Nnitrogen	1	14.007	14.007 w ≈ 8.25%	≈ 8.25%
Ooxygen	3	15.999	47.997 w ≈ 28.25%	≈ 28.25%
Σ = 169.874 ≈ 169.87 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Ag 63.50%

O 28.25%N 8.25%

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Molar masses of substances nearby

Formula	M, g/mol
C₈H₁₁NO₃	169.180
BaO₂ (barium peroxide)	169.33
BaS (barium sulfide)	169.39
AgNO₃ (silver nitrate)	169.87
Ba(OH)₂ (barium hydroxide)	171.34
CeO₂ (cerium(IV) oxide)	172.12
CaSO₄·2H₂O (calcium sulfate dihydrate)	172.16

FAQ

What is the molar mass of AgNO3?

M(AgNO₃) ≈ 169.87 g/mol

How to calculate the molar mass of AgNO₃?

Add up the atomic weights of all the atoms in the formula: 107.87 + 14.007 + 3 × 15.999 = 169.874 ≈ 169.87 g/mol.

How many grams are in 2 moles of AgNO₃?

m = n × M = 2 mol × 169.87 g/mol = 339.74 g.

See Also