Molar Mass of AgF (Silver Fluoride)

Molar Mass Calculator

What is the molar mass of AgF?

Answer

M(AgF) ≈

126.87 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ag: 107.87.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Agsilver	1	107.87	107.87 w ≈ 85.03%	≈ 85.03%
Ffluorine	1	18.998	18.998 w ≈ 14.97%	≈ 14.97%
Σ = 126.868 ≈ 126.87 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Ag 85.03%

F 14.97%

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Molar masses of substances nearby

Formula	M, g/mol
C₂H₆O₆	126.064
C₅H₆N₂O₂ (thymine)	126.115
FeCl₂ (ferrous chloride)	126.75
AgF (silver fluoride)	126.87
I (iodine)	126.90
Te (tellurium)	127.60
HI (hydrogen iodide)	127.91

FAQ

What is the molar mass of AgF?

M(AgF) ≈ 126.87 g/mol

How to calculate the molar mass of AgF?

Add up the atomic weights of all the atoms in the formula: 107.87 + 18.998 = 126.868 ≈ 126.87 g/mol.

How many grams are in 2 moles of AgF?

m = n × M = 2 mol × 126.87 g/mol = 253.74 g.

See Also