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    Cube Root of 3136

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    Cube root of

    What is the cube root of 3,136?

    Answer

    ∛3,136 =
    4∛49 ≈ 14.6372

    Real cube root: the only number whose cube is 3,136.

    ≈ — rounded to 4 decimal places. 3,136 is not the cube of a rational number, so ∛3,136 is irrational: its decimal expansion never ends and never repeats.

    Prime factors
    3,136 = (2 × 2 × 2) × (2 × 2 × 2) × 7 × 7 = 2⁶ × 7²
    Take out of the root
    ∛3,136 = ∛((2³)² × 49) = 2² × ∛49 = 4∛49
    Between cubes
    14³ = 2,744 < 3,136 < 3,375 = 15³, so 14 < ∛3,136 < 15 and ∛3,136 ≈ 14.6372

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    https://calculat.io/en/number/cube-root/3136Copy
    <a href="https://calculat.io/en/number/cube-root/3136">Cube Root of 3136 (∛3136): Exact Value and Decimal</a>Copy
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    Cube Root of 3136 (∛3136): Exact Value and Decimal. ∛3,136 = 4∛49 ≈ 14.6372. 3,136 = 4³ × 49, so 4 comes out of the root. Prime factors in threes and a check.
    https://calculat.io/en/number/cube-root/3136/generated.jpgCopy

    FAQ

    What is the cube root of 3,136?

    ∛3,136 = 4∛49 ≈ 14.6372

    How to simplify ∛3,136?

    Factor 3,136 into primes: 3,136 = 2 × 2 × 2 × 2 × 2 × 2 × 7 × 7. Each triple of equal factors is a cube and comes out of the root as one factor; the rest stays under it: ∛3,136 = ∛((2³)² × 49) = 4∛49.

    Is ∛3,136 a rational number?

    No: 3,136 is not the cube of a rational number, and the cube root of a fraction p/q in lowest terms is rational only when p and q are both cubes. So ∛3,136 is irrational; its decimal never ends and never repeats: ∛3,136 ≈ 14.6372.