Molar Mass of Zn(OH)2 (Zinc Hydroxide)
Molar Mass Calculator
What is the molar mass of Zn(OH)2?
Answer
M(Zn(OH)2) ≈
99.39 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Zn: 65.38.
Zn(OH)2 = Zn + 2 × (O + H) → Zn 1, O 2, H 2
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Znzinc | 1 | 65.38 | 65.38 w ≈ 65.78% | ≈ 65.78% |
| Ooxygen | 2 | 15.999 | 31.998 w ≈ 32.19% | ≈ 32.19% |
| Hhydrogen | 2 | 1.0080 | 2.0160 w ≈ 2.03% | ≈ 2.03% |
| Σ = 99.394 ≈ 99.39 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Zn 65.78%
O 32.19%H 2.03%
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FAQ
What is the molar mass of Zn(OH)2?
M(Zn(OH)₂) ≈ 99.39 g/mol
How to calculate the molar mass of Zn(OH)₂?
Add up the atomic weights of all the atoms in the formula: 65.38 + 2 × 15.999 + 2 × 1.0080 = 99.394 ≈ 99.39 g/mol.
How many grams are in 2 moles of Zn(OH)₂?
m = n × M = 2 mol × 99.39 g/mol = 198.78 g.
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