Molar Mass of Sr(NO3)2 (Strontium Nitrate)

Molar Mass Calculator

What is the molar mass of Sr(NO₃)₂?

Answer

M(Sr(NO₃)₂) ≈

211.63 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Sr: 87.62.

Sr(NO₃)₂ = Sr + 2 × (N + 3 O) → Sr 1, N 2, O 6

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Srstrontium	1	87.62	87.62 w ≈ 41.40%	≈ 41.40%
Nnitrogen	2	14.007	28.014 w ≈ 13.24%	≈ 13.24%
Ooxygen	6	15.999	95.994 w ≈ 45.36%	≈ 45.36%
Σ = 211.628 ≈ 211.63 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 45.36%Sr 41.40%

N 13.24%

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Molar masses of substances nearby

Formula	M, g/mol
PCl₅ (phosphorus pentachloride)	208.22
BaCl₂ (barium chloride)	208.23
Bi (bismuth)	208.98
Sr(NO₃)₂ (strontium nitrate)	211.63
K₃PO₄ (tribasic potassium phosphate)	212.264
Al(NO₃)₃ (aluminum nitrate)	212.994
KIO₃ (potassium iodate)	214.00

FAQ

What is the molar mass of Sr(NO3)2?

M(Sr(NO₃)₂) ≈ 211.63 g/mol

How to calculate the molar mass of Sr(NO₃)₂?

Add up the atomic weights of all the atoms in the formula: 87.62 + 2 × 14.007 + 6 × 15.999 = 211.628 ≈ 211.63 g/mol.

How many grams are in 2 moles of Sr(NO₃)₂?

m = n × M = 2 mol × 211.63 g/mol = 423.26 g.

See Also