Molar Mass of Sr(OH)2 (Strontium Hydroxide)
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What is the molar mass of Sr(OH)2?
Answer
M(Sr(OH)2) ≈
121.63 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Sr: 87.62.
Sr(OH)2 = Sr + 2 × (O + H) → Sr 1, O 2, H 2
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Srstrontium | 1 | 87.62 | 87.62 w ≈ 72.04% | ≈ 72.04% |
| Ooxygen | 2 | 15.999 | 31.998 w ≈ 26.31% | ≈ 26.31% |
| Hhydrogen | 2 | 1.0080 | 2.0160 w ≈ 1.66% | ≈ 1.66% |
| Σ = 121.634 ≈ 121.63 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Sr 72.04%
O 26.31%H 1.66%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| C₈H₈O (acetophenone) | 120.151 |
| MgSO₄ (magnesium sulfate) | 120.36 |
| C₄H₁₁NO₃ (tromethamine) | 121.136 |
| Sr(OH)₂ (strontium hydroxide) | 121.63 |
| Sb (antimony) | 121.76 |
| Na₂SiO₃ (sodium metasilicate) | 122.062 |
| C₆H₅COOH (benzoic acid) | 122.123 |