Molar Mass of NaH2PO4 (Monosodium Phosphate)

Molar Mass Calculator

What is the molar mass of NaH₂PO₄?

Answer

M(NaH₂PO₄) =

119.976 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nasodium	1	22.990	22.990 w ≈ 19.16%	≈ 19.16%
Hhydrogen	2	1.0080	2.0160 w ≈ 1.68%	≈ 1.68%
Pphosphorus	1	30.974	30.974 w ≈ 25.82%	≈ 25.82%
Ooxygen	4	15.999	63.996 w ≈ 53.34%	≈ 53.34%
Σ = 119.976 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 53.34%

P 25.82%Na 19.16%H 1.68%

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Molar masses of substances nearby

Formula	M, g/mol
CHCl₃ (chloroform)	119.37
HMnO₄ (permanganic acid)	119.942
FeS₂ (ferrous disulfide)	119.97
NaH₂PO₄ (monosodium phosphate)	119.976
NaHSO₄ (sodium bisulfate)	120.05
C₄H₈O₄	120.104
C₈H₈O (acetophenone)	120.151

FAQ

What is the molar mass of NaH2PO4?

M(NaH₂PO₄) = 119.976 g/mol

How to calculate the molar mass of NaH₂PO₄?

Add up the atomic weights of all the atoms in the formula: 22.990 + 2 × 1.0080 + 30.974 + 4 × 15.999 = 119.976 g/mol.

How many grams are in 2 moles of NaH₂PO₄?

m = n × M = 2 mol × 119.976 g/mol = 239.952 g.

See Also