Molar Mass of NaBr (Sodium Bromide)
Molar Mass Calculator
What is the molar mass of NaBr?
Answer
M(NaBr) =
102.894 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Nasodium | 1 | 22.990 | 22.990 w ≈ 22.34% | ≈ 22.34% |
| Brbromine | 1 | 79.904 | 79.904 w ≈ 77.66% | ≈ 77.66% |
| Σ = 102.894 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Br 77.66%
Na 22.34%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| Al₂O₃ (aluminium oxide) | 101.961 |
| C₄H₆O₃ (acetic anhydride) | 102.089 |
| C₆H₁₃OH | 102.177 |
| NaBr (sodium bromide) | 102.894 |
| Rh (rhodium) | 102.91 |
| Cr(OH)₃ | 103.017 |
| ZnF₂ (zinc fluoride) | 103.38 |
FAQ
What is the molar mass of NaBr?
M(NaBr) = 102.894 g/mol
How to calculate the molar mass of NaBr?
Add up the atomic weights of all the atoms in the formula: 22.990 + 79.904 = 102.894 g/mol.
How many grams are in 2 moles of NaBr?
m = n × M = 2 mol × 102.894 g/mol = 205.788 g.
See Also
- Molar Mass of Na2HPO4 (Dibasic Sodium Phosphate)
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- Молярная масса NaBr (бромид натрия): расчёт
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