Molar Mass of Na3PO4 (Trisodium Phosphate)
Molar Mass Calculator
What is the molar mass of Na3PO4?
Answer
M(Na3PO4) =
163.940 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Nasodium | 3 | 22.990 | 68.970 w ≈ 42.07% | ≈ 42.07% |
| Pphosphorus | 1 | 30.974 | 30.974 w ≈ 18.89% | ≈ 18.89% |
| Ooxygen | 4 | 15.999 | 63.996 w ≈ 39.04% | ≈ 39.04% |
| Σ = 163.940 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Na 42.07%O 39.04%
P 18.89%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| C₁₀H₁₄N₂ ((−)-nicotine) | 162.236 |
| C₆H₁₀OS₂ (allicin) | 162.27 |
| Dy (dysprosium) | 162.50 |
| Na₃PO₄ (trisodium phosphate) | 163.940 |
| Ca(NO₃)₂ (calcium nitrate) | 164.086 |
| Ho (holmium) | 164.93 |
| C₉H₁₁NO₂ (phenylalanine) | 165.192 |
FAQ
What is the molar mass of Na3PO4?
M(Na₃PO₄) = 163.940 g/mol
How to calculate the molar mass of Na₃PO₄?
Add up the atomic weights of all the atoms in the formula: 3 × 22.990 + 30.974 + 4 × 15.999 = 163.940 g/mol.
How many grams are in 2 moles of Na₃PO₄?
m = n × M = 2 mol × 163.940 g/mol = 327.880 g.
See Also
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