Molar Mass of LiBr (Lithium Bromide)

Molar Mass Calculator

What is the molar mass of LiBr?

Answer

M(LiBr) ≈

86.84 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Li: 6.94.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Lilithium	1	6.94	6.94 w ≈ 7.99%	≈ 7.99%
Brbromine	1	79.904	79.904 w ≈ 92.01%	≈ 92.01%
Σ = 86.844 ≈ 86.84 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Br 92.01%

Li 7.99%

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Molar masses of substances nearby

Formula	M, g/mol
Rb (rubidium)	85.468
C₄H₆O₂ (methacrylic acid)	86.090
C₆H₁₄ (hexane)	86.178
LiBr (lithium bromide)	86.84
MnO₂	86.936
Sr (strontium)	87.62
FeS (iron(II) sulfide)	87.91

FAQ

What is the molar mass of LiBr?

M(LiBr) ≈ 86.84 g/mol

How to calculate the molar mass of LiBr?

Add up the atomic weights of all the atoms in the formula: 6.94 + 79.904 = 86.844 ≈ 86.84 g/mol.

How many grams are in 2 moles of LiBr?

m = n × M = 2 mol × 86.84 g/mol = 173.68 g.

See Also