Molar Mass of KBrO3 (Potassium Bromate)
Molar Mass Calculator
What is the molar mass of KBrO3?
Answer
M(KBrO3) =
166.999 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Kpotassium | 1 | 39.098 | 39.098 w ≈ 23.41% | ≈ 23.41% |
| Brbromine | 1 | 79.904 | 79.904 w ≈ 47.85% | ≈ 47.85% |
| Ooxygen | 3 | 15.999 | 47.997 w ≈ 28.74% | ≈ 28.74% |
| Σ = 166.999 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Br 47.85%
O 28.74%K 23.41%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| C₉H₁₁NO₂ (phenylalanine) | 165.192 |
| KI (potassium iodide) | 166.00 |
| C₈H₆O₄ (terephthalic acid) | 166.132 |
| KBrO₃ (potassium bromate) | 166.999 |
| Er (erbium) | 167.26 |
| Tm (thulium) | 168.93 |
| C₃H₈NO₅P (glyphosate) | 169.073 |
FAQ
What is the molar mass of KBrO3?
M(KBrO₃) = 166.999 g/mol
How to calculate the molar mass of KBrO₃?
Add up the atomic weights of all the atoms in the formula: 39.098 + 79.904 + 3 × 15.999 = 166.999 g/mol.
How many grams are in 2 moles of KBrO₃?
m = n × M = 2 mol × 166.999 g/mol = 333.998 g.
See Also
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