Molar Mass of K2HPO4 (Dibasic Potassium Phosphate)

Molar Mass Calculator

What is the molar mass of K₂HPO₄?

Answer

M(K₂HPO₄) =

174.174 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Kpotassium	2	39.098	78.196 w ≈ 44.90%	≈ 44.90%
Hhydrogen	1	1.0080	1.0080 w ≈ 0.58%	≈ 0.58%
Pphosphorus	1	30.974	30.974 w ≈ 17.78%	≈ 17.78%
Ooxygen	4	15.999	63.996 w ≈ 36.74%	≈ 36.74%
Σ = 174.174 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

K 44.90%O 36.74%

P 17.78%H 0.58%

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Molar masses of substances nearby

Formula	M, g/mol
CaSO₄·2H₂O (calcium sulfate dihydrate)	172.16
Yb (ytterbium)	173.05
C₆H₇NO₃S (sulfanilic acid)	173.19
K₂HPO₄ (dibasic potassium phosphate)	174.174
C₆H₁₄N₄O₂ (L-arginine)	174.204
K₂SO₄ (potassium sulfate)	174.25
Lu (lutetium)	174.97

FAQ

What is the molar mass of K2HPO4?

M(K₂HPO₄) = 174.174 g/mol

How to calculate the molar mass of K₂HPO₄?

Add up the atomic weights of all the atoms in the formula: 2 × 39.098 + 1.0080 + 30.974 + 4 × 15.999 = 174.174 g/mol.

How many grams are in 2 moles of K₂HPO₄?

m = n × M = 2 mol × 174.174 g/mol = 348.348 g.

See Also