Molar Mass of Cr2(SO4)3 (Chromium(III) Sulfate)

Molar Mass Calculator

What is the molar mass of Cr₂(SO₄)₃?

Answer

M(Cr₂(SO₄)₃) =

392.16 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Cr₂(SO₄)₃ = 2 Cr + 3 × (S + 4 O) → Cr 2, S 3, O 12

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Crchromium	2	51.996	103.992 w ≈ 26.52%	≈ 26.52%
Ssulfur	3	32.06	96.18 w ≈ 24.53%	≈ 24.53%
Ooxygen	12	15.999	191.988 w ≈ 48.96%	≈ 48.96%
Σ = 392.16 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 48.96%

Cr 26.52%S 24.53%

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Molar masses of substances nearby

Formula	M, g/mol
Na₂B₄O₇·10H₂O	381.36
Zn₃(PO₄)₂ (zinc phosphate)	386.08
BaI₂ (barium iodide)	391.13
Cr₂(SO₄)₃ (chromium(III) sulfate)	392.16
CHI₃ (iodoform)	393.72
C₁₂H₁₉Cl₃O₈ (sucralose)	397.63
Fe₂(SO₄)₃ (ferric sulfate)	399.86

FAQ

What is the molar mass of Cr2(SO4)3?

M(Cr₂(SO₄)₃) = 392.16 g/mol

How to calculate the molar mass of Cr₂(SO₄)₃?

Add up the atomic weights of all the atoms in the formula: 2 × 51.996 + 3 × 32.06 + 12 × 15.999 = 392.16 g/mol.

How many grams are in 2 moles of Cr₂(SO₄)₃?

m = n × M = 2 mol × 392.16 g/mol = 784.32 g.

See Also