Molar Mass of C6H7NO3S (Sulfanilic Acid)
Molar Mass Calculator
What is the molar mass of C6H7NO3S?
Answer
M(C6H7NO3S) ≈
173.19 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Ccarbon | 6 | 12.011 | 72.066 w ≈ 41.61% | ≈ 41.61% |
| Hhydrogen | 7 | 1.0080 | 7.0560 w ≈ 4.07% | ≈ 4.07% |
| Nnitrogen | 1 | 14.007 | 14.007 w ≈ 8.09% | ≈ 8.09% |
| Ooxygen | 3 | 15.999 | 47.997 w ≈ 27.71% | ≈ 27.71% |
| Ssulfur | 1 | 32.06 | 32.06 w ≈ 18.51% | ≈ 18.51% |
| Σ = 173.186 ≈ 173.19 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
C 41.61%
O 27.71%S 18.51%N 8.09%H 4.07%
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FAQ
What is the molar mass of C6H7NO3S?
M(C₆H₇NO₃S) ≈ 173.19 g/mol
How to calculate the molar mass of C₆H₇NO₃S?
Add up the atomic weights of all the atoms in the formula: 6 × 12.011 + 7 × 1.0080 + 14.007 + 3 × 15.999 + 32.06 = 173.186 ≈ 173.19 g/mol.
How many grams are in 2 moles of C₆H₇NO₃S?
m = n × M = 2 mol × 173.19 g/mol = 346.38 g.
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