Molar Mass of C4H11NO3 (Tromethamine)

Molar Mass Calculator

What is the molar mass of C₄H₁₁NO₃?

Answer

M(C₄H₁₁NO₃) =

121.136 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	4	12.011	48.044 w ≈ 39.66%	≈ 39.66%
Hhydrogen	11	1.0080	11.0880 w ≈ 9.15%	≈ 9.15%
Nnitrogen	1	14.007	14.007 w ≈ 11.56%	≈ 11.56%
Ooxygen	3	15.999	47.997 w ≈ 39.62%	≈ 39.62%
Σ = 121.136 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 39.66%O 39.62%

N 11.56%H 9.15%

Related Calculations

See Also

Liters to Kilograms - How many kilograms are in a liter of water, honey, gasoline, sand and other substances — by density
Grams to Kg - Convert Grams to Kilograms
Percentage Calculator: Fraction to Percent - What percentage one number is of another? Convert fraction into a percentage
Scientific Calculator with Memory & History - Free Engineering Calculator Online with Memory Function, Operation History, Logarithms & Trigonometry. Similar to ti-83, ti-84, ti-89

Recalculate with different values ↑

Molar masses of substances nearby

Formula	M, g/mol
C₄H₈O₄	120.104
C₈H₈O (acetophenone)	120.151
MgSO₄ (magnesium sulfate)	120.36
C₄H₁₁NO₃ (tromethamine)	121.136
Sr(OH)₂ (strontium hydroxide)	121.63
Sb (antimony)	121.76
Na₂SiO₃ (sodium metasilicate)	122.062

FAQ

What is the molar mass of C4H11NO3?

M(C₄H₁₁NO₃) = 121.136 g/mol

How to calculate the molar mass of C₄H₁₁NO₃?

Add up the atomic weights of all the atoms in the formula: 4 × 12.011 + 11 × 1.0080 + 14.007 + 3 × 15.999 = 121.136 g/mol.

How many grams are in 2 moles of C₄H₁₁NO₃?

m = n × M = 2 mol × 121.136 g/mol = 242.272 g.

See Also