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    Molar Mass of C4H10 (Butane)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C4H10?

    Answer

    M(C4H10) =
    58.124 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon412.01148.044 w ≈ 82.66%
    Hhydrogen101.008010.0800 w ≈ 17.34%
    Σ = 58.124 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    H 17.34%

    Related Calculations

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    Molar Mass of C4H10 (Butane): Step by Step. M(C4H10) = 58.124 g/mol: 4 × 12.011 (C) + 10 × 1.0080 (H). Mass fractions: C 82.66%, H 17.34%.
    https://calculat.io/en/other/molar-mass/c4h10/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    MgS (magnesium sulfide)56.37
    C₃H₆O (acetone)58.080
    KF (potassium fluoride)58.096
    C₄H₁₀ (butane)58.124
    Mg(OH)₂ (magnesium hydroxide)58.319
    NaCl (sodium chloride)58.44
    Ni (nickel)58.693
    Recalculate with different values ↑

    FAQ

    What is the molar mass of C4H10?

    M(C₄H₁₀) = 58.124 g/mol

    How to calculate the molar mass of C₄H₁₀?

    Add up the atomic weights of all the atoms in the formula: 4 × 12.011 + 10 × 1.0080 = 58.124 g/mol.

    How many grams are in 2 moles of C₄H₁₀?

    m = n × M = 2 mol × 58.124 g/mol = 116.248 g.

    See Also