Molar Mass of BaSO4 (Barium Sulfate)

Molar Mass Calculator

What is the molar mass of BaSO₄?

Answer

M(BaSO₄) ≈

233.39 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ba: 137.33, S: 32.06.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Babarium	1	137.33	137.33 w ≈ 58.84%	≈ 58.84%
Ssulfur	1	32.06	32.06 w ≈ 13.74%	≈ 13.74%
Ooxygen	4	15.999	63.996 w ≈ 27.42%	≈ 27.42%
Σ = 233.386 ≈ 233.39 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Ba 58.84%

O 27.42%S 13.74%

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Molar masses of substances nearby

Formula	M, g/mol
Ag₂O (silver oxide)	231.74
Th (thorium)	232.04
HgS (mercury(II) sulfide)	232.65
BaSO₄ (barium sulfate)	233.39
Ca(H₂PO₄)₂ (monocalcium phosphate)	234.050
AgI (silver iodide)	234.77
CdN₂O₆ (cadmium nitrate)	236.42

FAQ

What is the molar mass of BaSO4?

M(BaSO₄) ≈ 233.39 g/mol

How to calculate the molar mass of BaSO₄?

Add up the atomic weights of all the atoms in the formula: 137.33 + 32.06 + 4 × 15.999 = 233.386 ≈ 233.39 g/mol.

How many grams are in 2 moles of BaSO₄?

m = n × M = 2 mol × 233.39 g/mol = 466.78 g.

See Also