Molar Mass of AlF3 (Aluminum Fluoride)
Molar Mass Calculator
What is the molar mass of AlF3?
Answer
M(AlF3) =
83.976 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Alaluminium | 1 | 26.982 | 26.982 w ≈ 32.13% | ≈ 32.13% |
| Ffluorine | 3 | 18.998 | 56.994 w ≈ 67.87% | ≈ 67.87% |
| Σ = 83.976 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
F 67.87%
Al 32.13%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| H₂SO₃ (sulfurous acid) | 82.07 |
| C₆H₁₀ (cyclohexene) | 82.146 |
| Kr (krypton) | 83.798 |
| AlF₃ (aluminum fluoride) | 83.976 |
| NaHCO₃ (sodium bicarbonate) | 84.006 |
| CHKO₂ (potassium formate) | 84.115 |
| C₆H₁₂ (cyclohexane) | 84.162 |
FAQ
What is the molar mass of AlF3?
M(AlF₃) = 83.976 g/mol
How to calculate the molar mass of AlF₃?
Add up the atomic weights of all the atoms in the formula: 26.982 + 3 × 18.998 = 83.976 g/mol.
How many grams are in 2 moles of AlF₃?
m = n × M = 2 mol × 83.976 g/mol = 167.952 g.
See Also
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- Молярная масса AlF3 (трифторид алюминия): расчёт
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