Molar Mass of Al(OH)3 (Aluminum Hydroxide)

Molar Mass Calculator

What is the molar mass of Al(OH)₃?

Answer

M(Al(OH)₃) =

78.003 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Al(OH)₃ = Al + 3 × (O + H) → Al 1, O 3, H 3

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Alaluminium	1	26.982	26.982 w ≈ 34.59%	≈ 34.59%
Ooxygen	3	15.999	47.997 w ≈ 61.53%	≈ 61.53%
Hhydrogen	3	1.0080	3.0240 w ≈ 3.88%	≈ 3.88%
Σ = 78.003 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 61.53%

Al 34.59%H 3.88%

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Molar masses of substances nearby

Formula	M, g/mol
C₃H₈O₂ ((RS)-propylene glycol)	76.095
CS₂ (carbon disulfide)	76.13
CH₃COONH₄ (ammonium acetate)	77.083
Al(OH)₃ (aluminum hydroxide)	78.003
Na₂S (sodium sulfide)	78.04
CaF₂ (calcium fluoride)	78.074
H₂SiO₃ (metasilicic acid)	78.098

FAQ

What is the molar mass of Al(OH)3?

M(Al(OH)₃) = 78.003 g/mol

How to calculate the molar mass of Al(OH)₃?

Add up the atomic weights of all the atoms in the formula: 26.982 + 3 × 15.999 + 3 × 1.0080 = 78.003 g/mol.

How many grams are in 2 moles of Al(OH)₃?

m = n × M = 2 mol × 78.003 g/mol = 156.006 g.

See Also