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    Cube Root of 23328

    Cube Root Calculator
    Cube root of

    What is the cube root of 23,328?

    Answer

    ∛23,328 =
    18∛4 ≈ 28.5732

    Real cube root: the only number whose cube is 23,328.

    ≈ — rounded to 4 decimal places. 23,328 is not the cube of a rational number, so ∛23,328 is irrational: its decimal expansion never ends and never repeats.

    Prime factors
    23,328 = (2 × 2 × 2) × 2 × 2 × (3 × 3 × 3) × (3 × 3 × 3) = 2⁵ × 3⁶
    Take out of the root
    ∛23,328 = ∛(2³ × (3³)² × 4) = 2 × 3² × ∛4 = 18∛4
    Between cubes
    28³ = 21,952 < 23,328 < 24,389 = 29³, so 28 < ∛23,328 < 29 and ∛23,328 ≈ 28.5732

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    https://calculat.io/en/number/cube-root/23328Copy
    <a href="https://calculat.io/en/number/cube-root/23328">Cube Root of 23328 (∛23328): Exact Value and Decimal</a>Copy
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    Cube Root of 23328 (∛23328): Exact Value and Decimal. ∛23,328 = 18∛4 ≈ 28.5732. 23,328 = 18³ × 4, so 18 comes out of the root. Prime factors in threes and a check.
    https://calculat.io/en/number/cube-root/23328/generated.jpgCopy

    Cube roots of nearby values

    FAQ

    What is the cube root of 23,328?

    ∛23,328 = 18∛4 ≈ 28.5732

    How to simplify ∛23,328?

    Factor 23,328 into primes: 23,328 = 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 3 × 3 × 3. Each triple of equal factors is a cube and comes out of the root as one factor; the rest stays under it: ∛23,328 = ∛(2³ × (3³)² × 4) = 18∛4.

    Is ∛23,328 a rational number?

    No: 23,328 is not the cube of a rational number, and the cube root of a fraction p/q in lowest terms is rational only when p and q are both cubes. So ∛23,328 is irrational; its decimal never ends and never repeats: ∛23,328 ≈ 28.5732.