15 Choose 14

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What is 15 choose 14?

Answer

15 choose 14 is
15

Order doesn't matter, no repeats: 15 ways to choose 14 of 15 items.

Choosing 14 of 15 is the same as leaving 1 out: C(15, 14) = C(15, 1).

C(15, 14) = 15! / (14! · 1!)

= C(15, 1)

= 15 / 1

= 15

If order matters (permutations): P(15, 14) = 15 × 14 × 13 × … × 2 = 1,307,674,368,000 — each combination in 14! = 87,178,291,200 orders.

Row sum: 215 = 32,768 — all subsets of 15 items.

See Also

FAQ

What is 15 choose 14?

15 choose 14 is 15

Why is 15 choose 14 the same as 15 choose 1?

Every way to choose 14 of 15 items leaves exactly 1 behind, so choosing 14 and choosing which one to leave out are the same count: 15 choose 14 = 15 choose 1 = 15. In the formula n! / (k! (n − k)!) the two factorials below just swap places.

How many ways are there if order matters?

P(15, 14) = 1,307,674,368,000. Each of the 15 combinations can be put in order in 14! = 87,178,291,200 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.