14 Choose 7
Combination Calculator
What is 14 choose 7?
Answer
14 choose 7 is
3,432
Order doesn't matter, no repeats: 3,432 ways to choose 7 of 14 items.
C(14, 7) = 14! / (7! · 7!)
= (14 × 13 × 12 × … × 8) / (7 × 6 × 5 × … × 1)
7 factors on top and bottom
= 17,297,280 / 5,040
= 3,432
If order matters (permutations): P(14, 7) = 14 × 13 × 12 × … × 8 = 17,297,280 — each combination in 7! = 5,040 orders.
| k | 14 choose k |
|---|---|
| 0 | 1 |
| 1 | 14 |
| 2 | 91 |
| 3 | 364 |
| 4 | 1,001 |
| 5 | 2,002 |
| 6 | 3,003 |
| 7 | 3,432 |
| 8 | 3,003 |
| 9 | 2,002 |
| 10 | 1,001 |
| 11 | 364 |
| 12 | 91 |
| 13 | 14 |
| 14 | 1 |
Row sum: 214 = 16,384 — all subsets of 14 items.
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n choose 7 for other n
FAQ
What is 14 choose 7?
14 choose 7 is 3,432
Why is 14 choose 7 the largest number in row 14?
In row 14 of Pascal's triangle the numbers grow towards the middle and shrink after it, because n choose k = n choose (n − k). With an even n the middle is k = 7, so 14 choose 7 = 3,432 is the largest: 14 choose 6 is only 3,003.
How many ways are there if order matters?
P(14, 7) = 17,297,280. Each of the 3,432 combinations can be put in order in 7! = 5,040 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.
See Also
- 13 Choose 11: Combinations C(13, 11)
- 13 Choose 12: Combinations C(13, 12)
- 13 Choose 13: Combinations C(13, 13)
- 14 Choose 0: Combinations C(14, 0)
- 14 Choose 1: Combinations C(14, 1)
- 14 Choose 2: Combinations C(14, 2)
- 14 Choose 3: Combinations C(14, 3)
- 14 Choose 4: Combinations C(14, 4)
- 14 Choose 5: Combinations C(14, 5)
- 14 Choose 6: Combinations C(14, 6)
- 14 Choose 8: Combinations C(14, 8)
- 14 Choose 9: Combinations C(14, 9)
- 14 Choose 10: Combinations C(14, 10)
- 14 Choose 11: Combinations C(14, 11)
- 14 Choose 12: Combinations C(14, 12)
- 14 Choose 13: Combinations C(14, 13)
- 14 Choose 14: Combinations C(14, 14)
- 15 Choose 0: Combinations C(15, 0)
- 15 Choose 1: Combinations C(15, 1)
- 15 Choose 2: Combinations C(15, 2)
- Число сочетаний из 14 по 7
- Combinaciones de 14 tomados de 7 en 7: C(14, 7)
- Combinação de 14 tomados 7 a 7: C(14, 7)