Molar Mass of NH4H2PO4 (Monobasic Ammonium Phosphate)

Molar Mass Calculator

What is the molar mass of NH₄H₂PO₄?

Answer

M(NH₄H₂PO₄) =

115.025 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nnitrogen	1	14.007	14.007 w ≈ 12.18%	≈ 12.18%
Hhydrogen	6	1.0080	6.0480 w ≈ 5.26%	≈ 5.26%
Pphosphorus	1	30.974	30.974 w ≈ 26.93%	≈ 26.93%
Ooxygen	4	15.999	63.996 w ≈ 55.64%	≈ 55.64%
Σ = 115.025 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 55.64%

P 26.93%N 12.18%H 5.26%

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Molar masses of substances nearby

Formula	M, g/mol
C₈H₁₈ (octane)	114.232
In (indium)	114.82
MnCO₃ (manganese carbonate)	114.946
NH₄H₂PO₄ (monobasic ammonium phosphate)	115.025
C₅H₉NO₂ (DL-proline)	115.132
C₄H₄O₄ (fumaric acid)	116.072
CH₃CH₂CH₂CO₂CH₂CH₃ (ethyl butyrate)	116.160

FAQ

What is the molar mass of NH4H2PO4?

M(NH₄H₂PO₄) = 115.025 g/mol

How to calculate the molar mass of NH₄H₂PO₄?

Add up the atomic weights of all the atoms in the formula: 14.007 + 6 × 1.0080 + 30.974 + 4 × 15.999 = 115.025 g/mol.

How many grams are in 2 moles of NH₄H₂PO₄?

m = n × M = 2 mol × 115.025 g/mol = 230.050 g.

See Also