Molar Mass of NaC3H5O2 (Sodium Propionate)

Molar Mass Calculator

What is the molar mass of NaC₃H₅O₂?

Answer

M(NaC₃H₅O₂) =

96.061 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nasodium	1	22.990	22.990 w ≈ 23.93%	≈ 23.93%
Ccarbon	3	12.011	36.033 w ≈ 37.51%	≈ 37.51%
Hhydrogen	5	1.0080	5.0400 w ≈ 5.25%	≈ 5.25%
Ooxygen	2	15.999	31.998 w ≈ 33.31%	≈ 33.31%
Σ = 96.061 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 37.51%

O 33.31%Na 23.93%H 5.25%

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Molar masses of substances nearby

Formula	M, g/mol
MgCl₂ (magnesium chloride)	95.21
CuS (copper monosulfide)	95.61
Mo (molybdenum)	95.95
NaC₃H₅O₂ (sodium propionate)	96.061
(NH₄)₂CO₃ (ammonium carbonate)	96.086
CoF₂ (cobalt(II) fluoride)	96.929
KSCN (potassium thiocyanate)	97.18

FAQ

What is the molar mass of NaC3H5O2?

M(NaC₃H₅O₂) = 96.061 g/mol

How to calculate the molar mass of NaC₃H₅O₂?

Add up the atomic weights of all the atoms in the formula: 22.990 + 3 × 12.011 + 5 × 1.0080 + 2 × 15.999 = 96.061 g/mol.

How many grams are in 2 moles of NaC₃H₅O₂?

m = n × M = 2 mol × 96.061 g/mol = 192.122 g.

See Also