Molar Mass of NaBH4 (Sodium Borohydride)
Molar Mass Calculator
What is the molar mass of NaBH4?
Answer
M(NaBH4) ≈
37.83 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — B: 10.81.
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Nasodium | 1 | 22.990 | 22.990 w ≈ 60.77% | ≈ 60.77% |
| Bboron | 1 | 10.81 | 10.81 w ≈ 28.57% | ≈ 28.57% |
| Hhydrogen | 4 | 1.0080 | 4.0320 w ≈ 10.66% | ≈ 10.66% |
| Σ = 37.832 ≈ 37.83 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Na 60.77%
B 28.57%H 10.66%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| Cl (chlorine) | 35.45 |
| HCl (hydrogen chloride) | 36.46 |
| NH₄F (ammonium fluoride) | 37.037 |
| NaBH₄ (sodium borohydride) | 37.83 |
| F₂ (fluorine) | 37.996 |
| K (potassium) | 39.098 |
| Ar (argon) | 39.95 |
FAQ
What is the molar mass of NaBH4?
M(NaBH₄) ≈ 37.83 g/mol
How to calculate the molar mass of NaBH₄?
Add up the atomic weights of all the atoms in the formula: 22.990 + 10.81 + 4 × 1.0080 = 37.832 ≈ 37.83 g/mol.
How many grams are in 2 moles of NaBH₄?
m = n × M = 2 mol × 37.83 g/mol = 75.66 g.
See Also
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