Molar Mass of MnSO4 (Manganese(II) Sulfate)

Molar Mass Calculator

What is the molar mass of MnSO₄?

Answer

M(MnSO₄) ≈

150.99 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Mnmanganese	1	54.938	54.938 w ≈ 36.38%	≈ 36.38%
Ssulfur	1	32.06	32.06 w ≈ 21.23%	≈ 21.23%
Ooxygen	4	15.999	63.996 w ≈ 42.38%	≈ 42.38%
Σ = 150.994 ≈ 150.99 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 42.38%Mn 36.38%

S 21.23%

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Molar masses of substances nearby

Formula	M, g/mol
C₁₀H₁₄O (thymol)	150.221
Sm (samarium)	150.36
SnO₂ (tin(IV) oxide)	150.71
MnSO₄ (manganese(II) sulfate)	150.99
C₈H₉NO₂ (paracetamol)	151.165
FeSO₄ (iron(II) sulfate)	151.90
Eu (europium)	151.96

FAQ

What is the molar mass of MnSO4?

M(MnSO₄) ≈ 150.99 g/mol

How to calculate the molar mass of MnSO₄?

Add up the atomic weights of all the atoms in the formula: 54.938 + 32.06 + 4 × 15.999 = 150.994 ≈ 150.99 g/mol.

How many grams are in 2 moles of MnSO₄?

m = n × M = 2 mol × 150.99 g/mol = 301.98 g.

See Also