Molar Mass of K2CrO4 (Potassium Chromate)
Molar Mass Calculator
What is the molar mass of K2CrO4?
Answer
M(K2CrO4) =
194.188 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Kpotassium | 2 | 39.098 | 78.196 w ≈ 40.27% | ≈ 40.27% |
| Crchromium | 1 | 51.996 | 51.996 w ≈ 26.78% | ≈ 26.78% |
| Ooxygen | 4 | 15.999 | 63.996 w ≈ 32.96% | ≈ 32.96% |
| Σ = 194.188 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
K 40.27%
O 32.96%Cr 26.78%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| CuI (cuprous iodide) | 190.45 |
| H₃C₆H₅O₇ (citric acid) | 192.123 |
| Ir (iridium) | 192.22 |
| K₂CrO₄ (potassium chromate) | 194.188 |
| C₈H₁₀N₄O₂ (caffeine) | 194.194 |
| Pt (platinum) | 195.08 |
| C₆H₁₂O₇ (D-gluconic acid) | 196.155 |
FAQ
What is the molar mass of K2CrO4?
M(K₂CrO₄) = 194.188 g/mol
How to calculate the molar mass of K₂CrO₄?
Add up the atomic weights of all the atoms in the formula: 2 × 39.098 + 51.996 + 4 × 15.999 = 194.188 g/mol.
How many grams are in 2 moles of K₂CrO₄?
m = n × M = 2 mol × 194.188 g/mol = 388.376 g.
See Also
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