Molar Mass of C6H14N4O2 (L-arginine)

Molar Mass Calculator

What is the molar mass of C₆H₁₄N₄O₂?

Answer

M(C₆H₁₄N₄O₂) =

174.204 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	6	12.011	72.066 w ≈ 41.37%	≈ 41.37%
Hhydrogen	14	1.0080	14.1120 w ≈ 8.10%	≈ 8.10%
Nnitrogen	4	14.007	56.028 w ≈ 32.16%	≈ 32.16%
Ooxygen	2	15.999	31.998 w ≈ 18.37%	≈ 18.37%
Σ = 174.204 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 41.37%

N 32.16%O 18.37%H 8.10%

Related Calculations

See Also

Liters to Kilograms - How many kilograms are in a liter of water, honey, gasoline, sand and other substances — by density
Grams to Kg - Convert Grams to Kilograms
Percentage Calculator: Fraction to Percent - What percentage one number is of another? Convert fraction into a percentage
Scientific Calculator with Memory & History - Free Engineering Calculator Online with Memory Function, Operation History, Logarithms & Trigonometry. Similar to ti-83, ti-84, ti-89

Recalculate with different values ↑

Molar masses of substances nearby

Formula	M, g/mol
Yb (ytterbium)	173.05
C₆H₇NO₃S (sulfanilic acid)	173.19
K₂HPO₄ (dibasic potassium phosphate)	174.174
C₆H₁₄N₄O₂ (L-arginine)	174.204
K₂SO₄ (potassium sulfate)	174.25
Lu (lutetium)	174.97
BaF₂ (barium fluoride)	175.33

FAQ

What is the molar mass of C6H14N4O2?

M(C₆H₁₄N₄O₂) = 174.204 g/mol

How to calculate the molar mass of C₆H₁₄N₄O₂?

Add up the atomic weights of all the atoms in the formula: 6 × 12.011 + 14 × 1.0080 + 4 × 14.007 + 2 × 15.999 = 174.204 g/mol.

How many grams are in 2 moles of C₆H₁₄N₄O₂?

m = n × M = 2 mol × 174.204 g/mol = 348.408 g.

See Also