Subtraction with Regrouping: 283 − 15

Subtraction with Regrouping Calculator
Minuend
Subtrahend

What is 283 − 15?

Answer

283 − 15 =
268

With regrouping: 1 borrow — from the tens

283 − 15 in a column. Above the columns: the values after borrowing — a crossed-out digit is replaced by the number above it; +10 marks a column that received a borrowed ten.
7+10
2 8(was 8, now 7)3 (was 3, now 13)
−15
268

Column by column: 283 − 15

  • Ones: 3 is less than 5 — borrow 1 ten: tens 8 → 7; 13 − 5 = 8 — write 8.
  • Tens: after borrowing, 7; 7 − 1 = 6 — write 6.
  • Hundreds: nothing to subtract — write 2.

283 − 15 = 268

Second check: 283 − 268 = 15

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Recalculate with different values ↑

Column subtractions of 15

ExampleDifference
100 − 1585
104 − 1589
107 − 1592
109 − 1594
113 − 1598
120 − 15105
151 − 15136
187 − 15172
218 − 15203
254 − 15239
283 − 15268
322 − 15307
363 − 15348
391 − 15376
417 − 15402
468 − 15453
500 − 15485
551 − 15536
593 − 15578
662 − 15647

FAQ

What is 283 − 15?

283 − 15 = 268

How do you check that 283 − 15 = 268?

Add the difference and the subtrahend: 268 + 15 = 283. Getting the minuend back means the difference is right.

How many times do you borrow in 283 − 15?

1 borrow: each time the top digit was smaller than the one below it, 1 was borrowed from the column on the left.

See Also