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    Subtraction with Regrouping: 283 − 15

    Subtraction with Regrouping Calculator
    Minuend
    Subtrahend

    What is 283 − 15?

    Answer

    283 − 15 =
    268

    With regrouping: 1 borrow — from the tens

    283 − 15 in a column. Above the columns: the values after borrowing — a crossed-out digit is replaced by the number above it; +10 marks a column that received a borrowed ten.
    7+10
    2 8(was 8, now 7)3 (was 3, now 13)
    −15
    268

    Column by column: 283 − 15

    • Ones: 3 is less than 5 — borrow 1 ten: tens 8 → 7; 13 − 5 = 8 — write 8.
    • Tens: after borrowing, 7; 7 − 1 = 6 — write 6.
    • Hundreds: nothing to subtract — write 2.

    283 − 15 = 268

    Second check: 283 − 268 = 15

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    <a href="https://calculat.io/en/number/long-subtraction/283--15">283 − 15 = 268 - Subtraction with Regrouping - Calculatio</a>Copy
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    283 − 15 = 268 - Subtraction with Regrouping. 283 − 15 = 268. Subtraction with regrouping step by step: 1 borrow, every digit of the difference and an addition check.
    https://calculat.io/en/number/long-subtraction/283--15/generated.jpgCopy

    Column subtractions of 15

    ExampleDifference
    100 − 1585
    104 − 1589
    107 − 1592
    109 − 1594
    113 − 1598
    120 − 15105
    151 − 15136
    187 − 15172
    218 − 15203
    254 − 15239
    283 − 15268
    322 − 15307
    363 − 15348
    391 − 15376
    417 − 15402
    468 − 15453
    500 − 15485
    551 − 15536
    593 − 15578
    662 − 15647
    Recalculate with different values ↑

    FAQ

    What is 283 − 15?

    283 − 15 = 268

    How do you check that 283 − 15 = 268?

    Add the difference and the subtrahend: 268 + 15 = 283. Getting the minuend back means the difference is right.

    How many times do you borrow in 283 − 15?

    1 borrow: each time the top digit was smaller than the one below it, 1 was borrowed from the column on the left.

    See Also