Subtraction with Regrouping: 1,031 − 453

Subtraction with Regrouping Calculator
Minuend
Subtrahend

What is 1,031 − 453?

Answer

1,031 − 453 =
578

With regrouping across a zero: 3 borrows — there are no hundreds to borrow from, so 1 thousand becomes 10 hundreds, and 1 hundred goes to the tens

1,031 − 453 in a column. Above the columns: the values after borrowing — a crossed-out digit is replaced by the number above it; +10 marks a column that received a borrowed ten.
0912+10
1(was 1, now 0)0(was 0, now 9)3(was 3, now 12)1 (was 1, now 11)
−453
578

Column by column: 1,031 − 453

  • Ones: 1 is less than 3 — borrow 1 ten: tens 3 → 2; 11 − 3 = 8 — write 8.
  • Tens: after borrowing, 2; 2 is less than 5 — borrow 1 thousand across the zero: thousands 1 → 0, hundreds 0 → 9; 12 − 5 = 7 — write 7.
  • Hundreds: after borrowing, 9; 9 − 4 = 5 — write 5.
  • Thousands: after borrowing, 0 — a leading zero is not written.

1,031 − 453 = 578

Second check: 1,031 − 578 = 453

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Recalculate with different values ↑

Column subtractions of 453

ExampleDifference
1,026 − 453573
1,027 − 453574
1,028 − 453575
1,029 − 453576
1,030 − 453577
1,031 − 453578
1,032 − 453579
1,033 − 453580
1,034 − 453581
1,035 − 453582
1,036 − 453583

FAQ

What is 1,031 − 453?

1,031 − 453 = 578

How do you check that 1,031 − 453 = 578?

Add the difference and the subtrahend: 578 + 453 = 1,031. Getting the minuend back means the difference is right.

How many times do you borrow in 1,031 − 453?

3 borrows: each time the top digit was smaller than the one below it, 1 was borrowed from the column on the left.

Why does 0 become 9 when borrowing in 1,031 − 453?

The zero has nothing to lend, so it first borrows 1 from its left neighbour and becomes 10; then it lends 1 to the column on its right and keeps 9.

See Also