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    Cube Root of 1280

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    Cube root of

    What is the cube root of 1,280?

    Answer

    ∛1,280 =
    4∛20 ≈ 10.8577

    Real cube root: the only number whose cube is 1,280.

    ≈ — rounded to 4 decimal places. 1,280 is not the cube of a rational number, so ∛1,280 is irrational: its decimal expansion never ends and never repeats.

    Prime factors
    1,280 = (2 × 2 × 2) × (2 × 2 × 2) × 2 × 2 × 5 = 2⁸ × 5
    Take out of the root
    ∛1,280 = ∛((2³)² × 20) = 2² × ∛20 = 4∛20
    Between cubes
    10³ = 1,000 < 1,280 < 1,331 = 11³, so 10 < ∛1,280 < 11 and ∛1,280 ≈ 10.8577

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    https://calculat.io/en/number/cube-root/1280Copy
    <a href="https://calculat.io/en/number/cube-root/1280">Cube Root of 1280 (∛1280): Exact Value and Decimal</a>Copy
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    Cube Root of 1280 (∛1280): Exact Value and Decimal. ∛1,280 = 4∛20 ≈ 10.8577. 1,280 = 4³ × 20, so 4 comes out of the root. Prime factors in threes and a check.
    https://calculat.io/en/number/cube-root/1280/generated.jpgCopy

    Cube roots of nearby values

    N∛N
    1,2002∛150 ≈ 10.6266
    1,210≈ 10.656
    1,225≈ 10.6999
    1,2804∛20 ≈ 10.8577
    1,2966∛6 ≈ 10.9027
    1,3233∛49 ≈ 10.9779
    1,33111
    Recalculate with different values ↑

    FAQ

    What is the cube root of 1,280?

    ∛1,280 = 4∛20 ≈ 10.8577

    How to simplify ∛1,280?

    Factor 1,280 into primes: 1,280 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 5. Each triple of equal factors is a cube and comes out of the root as one factor; the rest stays under it: ∛1,280 = ∛((2³)² × 20) = 4∛20.

    Is ∛1,280 a rational number?

    No: 1,280 is not the cube of a rational number, and the cube root of a fraction p/q in lowest terms is rational only when p and q are both cubes. So ∛1,280 is irrational; its decimal never ends and never repeats: ∛1,280 ≈ 10.8577.

    See Also