17 Choose 4
Combination Calculator
What is 17 choose 4?
Answer
17 choose 4 is
2,380
Order doesn't matter, no repeats: 2,380 ways to choose 4 of 17 items.
C(17, 4) = 17! / (4! · 13!)
= (17 × 16 × 15 × 14) / (4 × 3 × 2 × 1)
= 57,120 / 24
= 2,380
If order matters (permutations): P(17, 4) = 17 × 16 × 15 × 14 = 57,120 — each combination in 4! = 24 orders.
| k | 17 choose k |
|---|---|
| 0 | 1 |
| 1 | 17 |
| 2 | 136 |
| 3 | 680 |
| 4 | 2,380 |
| 5 | 6,188 |
| 6 | 12,376 |
| 7 | 19,448 |
| 8 | 24,310 |
| 9 | 24,310 |
| 10 | 19,448 |
| 11 | 12,376 |
| 12 | 6,188 |
| 13 | 2,380 |
| 14 | 680 |
| 15 | 136 |
| 16 | 17 |
| 17 | 1 |
Row sum: 217 = 131,072 — all subsets of 17 items.
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n choose 4 for other n
FAQ
What is 17 choose 4?
17 choose 4 is 2,380
Why is 17 choose 4 the same as 17 choose 13?
Every way to choose 4 of 17 items leaves exactly 13 behind, so choosing 4 and choosing which 13 to leave out are the same count: 17 choose 4 = 17 choose 13 = 2,380. In the formula n! / (k! (n − k)!) the two factorials below just swap places.
How many ways are there if order matters?
P(17, 4) = 57,120. Each of the 2,380 combinations can be put in order in 4! = 24 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.
See Also
- 16 Choose 11: Combinations C(16, 11)
- 16 Choose 12: Combinations C(16, 12)
- 16 Choose 13: Combinations C(16, 13)
- 16 Choose 14: Combinations C(16, 14)
- 16 Choose 15: Combinations C(16, 15)
- 16 Choose 16: Combinations C(16, 16)
- 17 Choose 0: Combinations C(17, 0)
- 17 Choose 1: Combinations C(17, 1)
- 17 Choose 2: Combinations C(17, 2)
- 17 Choose 3: Combinations C(17, 3)
- 17 Choose 5: Combinations C(17, 5)
- 17 Choose 6: Combinations C(17, 6)
- 17 Choose 7: Combinations C(17, 7)
- 17 Choose 8: Combinations C(17, 8)
- 17 Choose 9: Combinations C(17, 9)
- 17 Choose 10: Combinations C(17, 10)
- 17 Choose 11: Combinations C(17, 11)
- 17 Choose 12: Combinations C(17, 12)
- 17 Choose 13: Combinations C(17, 13)
- 17 Choose 14: Combinations C(17, 14)
- Число сочетаний из 17 по 4
- Combinaciones de 17 tomados de 4 en 4: C(17, 4)
- Combinação de 17 tomados 4 a 4: C(17, 4)