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    11 Choose 4

    Combination Calculator
    Total items (n)
    Items chosen (k)

    What is 11 choose 4?

    Answer

    11 choose 4 is
    330

    Order doesn't matter, no repeats: 330 ways to choose 4 of 11 items.

    C(11, 4) = 11! / (4! · 7!)

    = (11 × 10 × 9 × 8) / (4 × 3 × 2 × 1)
    = 7,920 / 24

    = 330

    If order matters (permutations): P(11, 4) = 11 × 10 × 9 × 8 = 7,920 — each combination in 4! = 24 orders.

    Row 11 of Pascal's triangle
    k11 choose k
    01
    111
    255
    3165
    4330
    5462
    6462
    7330
    8165
    955
    1011
    111

    Row sum: 211 = 2,048 — all subsets of 11 items.

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    https://calculat.io/en/number/combinations/11--4Copy
    <a href="https://calculat.io/en/number/combinations/11--4">11 Choose 4: Combinations C(11, 4) - Calculatio</a>Copy
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    11 Choose 4: Combinations C(11, 4). 11 choose 4 = 330: the number of ways to choose 4 of 11 items when order doesn't matter and nothing repeats. C(11, 4) = (11 × 10 × 9 × 8) / (4 × 3 × 2 × 1).
    https://calculat.io/en/number/combinations/11--4/generated.jpgCopy

    n choose 4 for other n

    n choose 4Answer
    4 choose 41
    5 choose 45
    6 choose 415
    7 choose 435
    8 choose 470
    9 choose 4126
    10 choose 4210
    11 choose 4330
    12 choose 4495
    13 choose 4715
    14 choose 41,001
    15 choose 41,365
    16 choose 41,820
    17 choose 42,380
    18 choose 43,060
    Recalculate with different values ↑

    FAQ

    What is 11 choose 4?

    11 choose 4 is 330

    Why is 11 choose 4 the same as 11 choose 7?

    Every way to choose 4 of 11 items leaves exactly 7 behind, so choosing 4 and choosing which 7 to leave out are the same count: 11 choose 4 = 11 choose 7 = 330. In the formula n! / (k! (n − k)!) the two factorials below just swap places.

    How many ways are there if order matters?

    P(11, 4) = 7,920. Each of the 330 combinations can be put in order in 4! = 24 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.

    See Also