14 Choose 10
Combination Calculator
What is 14 choose 10?
Answer
14 choose 10 is
1,001
Order doesn't matter, no repeats: 1,001 ways to choose 10 of 14 items.
Choosing 10 of 14 is the same as leaving 4 out: C(14, 10) = C(14, 4).
C(14, 10) = 14! / (10! · 4!)
= C(14, 4)
= (14 × 13 × 12 × 11) / (4 × 3 × 2 × 1)
= 24,024 / 24
= 1,001
If order matters (permutations): P(14, 10) = 14 × 13 × 12 × … × 5 = 3,632,428,800 — each combination in 10! = 3,628,800 orders.
| k | 14 choose k |
|---|---|
| 0 | 1 |
| 1 | 14 |
| 2 | 91 |
| 3 | 364 |
| 4 | 1,001 |
| 5 | 2,002 |
| 6 | 3,003 |
| 7 | 3,432 |
| 8 | 3,003 |
| 9 | 2,002 |
| 10 | 1,001 |
| 11 | 364 |
| 12 | 91 |
| 13 | 14 |
| 14 | 1 |
Row sum: 214 = 16,384 — all subsets of 14 items.
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n choose 10 for other n
FAQ
What is 14 choose 10?
14 choose 10 is 1,001
Why is 14 choose 10 the same as 14 choose 4?
Every way to choose 10 of 14 items leaves exactly 4 behind, so choosing 10 and choosing which 4 to leave out are the same count: 14 choose 10 = 14 choose 4 = 1,001. In the formula n! / (k! (n − k)!) the two factorials below just swap places.
How many ways are there if order matters?
P(14, 10) = 3,632,428,800. Each of the 1,001 combinations can be put in order in 10! = 3,628,800 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.
See Also
- 14 Choose 0: Combinations C(14, 0)
- 14 Choose 1: Combinations C(14, 1)
- 14 Choose 2: Combinations C(14, 2)
- 14 Choose 3: Combinations C(14, 3)
- 14 Choose 4: Combinations C(14, 4)
- 14 Choose 5: Combinations C(14, 5)
- 14 Choose 6: Combinations C(14, 6)
- 14 Choose 7: Combinations C(14, 7)
- 14 Choose 8: Combinations C(14, 8)
- 14 Choose 9: Combinations C(14, 9)
- 14 Choose 11: Combinations C(14, 11)
- 14 Choose 12: Combinations C(14, 12)
- 14 Choose 13: Combinations C(14, 13)
- 14 Choose 14: Combinations C(14, 14)
- 15 Choose 0: Combinations C(15, 0)
- 15 Choose 1: Combinations C(15, 1)
- 15 Choose 2: Combinations C(15, 2)
- 15 Choose 3: Combinations C(15, 3)
- 15 Choose 4: Combinations C(15, 4)
- 15 Choose 5: Combinations C(15, 5)
- Число сочетаний из 14 по 10
- Combinaciones de 14 tomados de 10 en 10: C(14, 10)
- Combinação de 14 tomados 10 a 10: C(14, 10)