Molar Mass of H3PO4 (Phosphoric Acid)
Molar Mass Calculator
What is the molar mass of H3PO4?
Answer
M(H3PO4) =
97.994 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Hhydrogen | 3 | 1.0080 | 3.0240 w ≈ 3.09% | ≈ 3.09% |
| Pphosphorus | 1 | 30.974 | 30.974 w ≈ 31.61% | ≈ 31.61% |
| Ooxygen | 4 | 15.999 | 63.996 w ≈ 65.31% | ≈ 65.31% |
| Σ = 97.994 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 65.31%
P 31.61%H 3.09%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| ZnS (zinc sulfide) | 97.44 |
| Cu(OH)₂ (cupric hydroxide) | 97.560 |
| NH₄Br (ammonium bromide) | 97.943 |
| H₃PO₄ (phosphoric acid) | 97.994 |
| C₄H₂O₃ (maleic anhydride) | 98.057 |
| H₂SO₄ (sulfuric acid) | 98.07 |
| CH₃COOK (potassium acetate) | 98.142 |
FAQ
What is the molar mass of H3PO4?
M(H₃PO₄) = 97.994 g/mol
How to calculate the molar mass of H₃PO₄?
Add up the atomic weights of all the atoms in the formula: 3 × 1.0080 + 30.974 + 4 × 15.999 = 97.994 g/mol.
How many grams are in 2 moles of H₃PO₄?
m = n × M = 2 mol × 97.994 g/mol = 195.988 g.
See Also
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- Молярная масса H3PO4 (ортофосфорная кислота): расчёт
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