Molar Mass of H3C6H5O7 (Citric Acid)

Molar Mass Calculator

What is the molar mass of H₃C₆H₅O₇?

Answer

M(H₃C₆H₅O₇) =

192.123 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Hhydrogen	8	1.0080	8.0640 w ≈ 4.20%	≈ 4.20%
Ccarbon	6	12.011	72.066 w ≈ 37.51%	≈ 37.51%
Ooxygen	7	15.999	111.993 w ≈ 58.29%	≈ 58.29%
Σ = 192.123 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 58.29%C 37.51%

H 4.20%

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Molar masses of substances nearby

Formula	M, g/mol
TiCl₄ (titanium tetrachloride)	189.67
Os (osmium)	190.23
CuI (cuprous iodide)	190.45
H₃C₆H₅O₇ (citric acid)	192.123
Ir (iridium)	192.22
K₂CrO₄ (potassium chromate)	194.188
C₈H₁₀N₄O₂ (caffeine)	194.194

FAQ

What is the molar mass of H3C6H5O7?

M(H₃C₆H₅O₇) = 192.123 g/mol

How to calculate the molar mass of H₃C₆H₅O₇?

Add up the atomic weights of all the atoms in the formula: 8 × 1.0080 + 6 × 12.011 + 7 × 15.999 = 192.123 g/mol.

How many grams are in 2 moles of H₃C₆H₅O₇?

m = n × M = 2 mol × 192.123 g/mol = 384.246 g.

See Also