Molar Mass of H3BO3 (Orthoboric Acid)
Molar Mass Calculator
What is the molar mass of H3BO3?
Answer
M(H3BO3) ≈
61.83 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — B: 10.81.
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Hhydrogen | 3 | 1.0080 | 3.0240 w ≈ 4.89% | ≈ 4.89% |
| Bboron | 1 | 10.81 | 10.81 w ≈ 17.48% | ≈ 17.48% |
| Ooxygen | 3 | 15.999 | 47.997 w ≈ 77.63% | ≈ 77.63% |
| Σ = 61.831 ≈ 61.83 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 77.63%
B 17.48%H 4.89%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| C₃H₇OH (propyl alcohol) | 60.096 |
| C₂H₈N₂ (ethylenediamine) | 60.100 |
| CH₃NO₂ (nitromethane) | 61.040 |
| H₃BO₃ (orthoboric acid) | 61.83 |
| Na₂O (sodium oxide) | 61.979 |
| H₂CO₃ (carbonic acid) | 62.024 |
| C₂H₆O₂ (ethylene glycol) | 62.068 |
FAQ
What is the molar mass of H3BO3?
M(H₃BO₃) ≈ 61.83 g/mol
How to calculate the molar mass of H₃BO₃?
Add up the atomic weights of all the atoms in the formula: 3 × 1.0080 + 10.81 + 3 × 15.999 = 61.831 ≈ 61.83 g/mol.
How many grams are in 2 moles of H₃BO₃?
m = n × M = 2 mol × 61.83 g/mol = 123.66 g.
See Also
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