Molar Mass of FeSO4 (Iron(II) Sulfate)

Molar Mass Calculator

What is the molar mass of FeSO₄?

Answer

M(FeSO₄) ≈

151.90 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Feiron	1	55.845	55.845 w ≈ 36.76%	≈ 36.76%
Ssulfur	1	32.06	32.06 w ≈ 21.11%	≈ 21.11%
Ooxygen	4	15.999	63.996 w ≈ 42.13%	≈ 42.13%
Σ = 151.901 ≈ 151.90 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 42.13%Fe 36.76%

S 21.11%

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Molar masses of substances nearby

Formula	M, g/mol
SnO₂ (tin(IV) oxide)	150.71
MnSO₄ (manganese(II) sulfate)	150.99
C₈H₉NO₂ (paracetamol)	151.165
FeSO₄ (iron(II) sulfate)	151.90
Eu (europium)	151.96
Cr₂O₃ (dichromium trioxide)	151.989
C₈H₈O₃	152.149

FAQ

What is the molar mass of FeSO4?

M(FeSO₄) ≈ 151.90 g/mol

How to calculate the molar mass of FeSO₄?

Add up the atomic weights of all the atoms in the formula: 55.845 + 32.06 + 4 × 15.999 = 151.901 ≈ 151.90 g/mol.

How many grams are in 2 moles of FeSO₄?

m = n × M = 2 mol × 151.90 g/mol = 303.80 g.

See Also