Molar Mass of Fe3O4 (Iron(II,III) Oxide)

Molar Mass Calculator

What is the molar mass of Fe₃O₄?

Answer

M(Fe₃O₄) =

231.531 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Feiron	3	55.845	167.535 w ≈ 72.36%	≈ 72.36%
Ooxygen	4	15.999	63.996 w ≈ 27.64%	≈ 27.64%
Σ = 231.531 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Fe 72.36%

O 27.64%

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Molar masses of substances nearby

Formula	M, g/mol
SbCl₃ (antimony trichloride)	228.11
C₁₄H₁₂O₃ (resveratrol)	228.247
Pa (protactinium)	231.04
Fe₃O₄ (iron(II,III) oxide)	231.531
Ag₂O (silver oxide)	231.74
Th (thorium)	232.04
HgS (mercury(II) sulfide)	232.65

FAQ

What is the molar mass of Fe3O4?

M(Fe₃O₄) = 231.531 g/mol

How to calculate the molar mass of Fe₃O₄?

Add up the atomic weights of all the atoms in the formula: 3 × 55.845 + 4 × 15.999 = 231.531 g/mol.

How many grams are in 2 moles of Fe₃O₄?

m = n × M = 2 mol × 231.531 g/mol = 463.062 g.

See Also