Molar Mass of Fe(OH)3 (Iron(III) Hydroxide)

Molar Mass Calculator

What is the molar mass of Fe(OH)₃?

Answer

M(Fe(OH)₃) =

106.866 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Fe(OH)₃ = Fe + 3 × (O + H) → Fe 1, O 3, H 3

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Feiron	1	55.845	55.845 w ≈ 52.26%	≈ 52.26%
Ooxygen	3	15.999	47.997 w ≈ 44.91%	≈ 44.91%
Hhydrogen	3	1.0080	3.0240 w ≈ 2.83%	≈ 2.83%
Σ = 106.866 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Fe 52.26%O 44.91%

H 2.83%

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Molar masses of substances nearby

Formula	M, g/mol
C₈H₁₀ (ethylbenzene)	106.168
Pd (palladium)	106.42
NaClO₃ (sodium chlorate)	106.44
Fe(OH)₃ (iron(III) hydroxide)	106.866
Ag (silver)	107.87
N₂O₅ (dinitrogen pentoxide)	108.009
C₂H₅Br (bromoethane)	108.966

FAQ

What is the molar mass of Fe(OH)3?

M(Fe(OH)₃) = 106.866 g/mol

How to calculate the molar mass of Fe(OH)₃?

Add up the atomic weights of all the atoms in the formula: 55.845 + 3 × 15.999 + 3 × 1.0080 = 106.866 g/mol.

How many grams are in 2 moles of Fe(OH)₃?

m = n × M = 2 mol × 106.866 g/mol = 213.732 g.

See Also