Molar Mass of CH3COONH4 (Ammonium Acetate)

Molar Mass Calculator

What is the molar mass of CH₃COONH₄?

Answer

M(CH₃COONH₄) =

77.083 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	2	12.011	24.022 w ≈ 31.16%	≈ 31.16%
Hhydrogen	7	1.0080	7.0560 w ≈ 9.15%	≈ 9.15%
Ooxygen	2	15.999	31.998 w ≈ 41.51%	≈ 41.51%
Nnitrogen	1	14.007	14.007 w ≈ 18.17%	≈ 18.17%
Σ = 77.083 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 41.51%

C 31.16%N 18.17%H 9.15%

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Molar masses of substances nearby

Formula	M, g/mol
N₂O₃ (dinitrogen trioxide)	76.011
C₃H₈O₂ ((RS)-propylene glycol)	76.095
CS₂ (carbon disulfide)	76.13
CH₃COONH₄ (ammonium acetate)	77.083
Al(OH)₃ (aluminum hydroxide)	78.003
Na₂S (sodium sulfide)	78.04
CaF₂ (calcium fluoride)	78.074

FAQ

What is the molar mass of CH3COONH4?

M(CH₃COONH₄) = 77.083 g/mol

How to calculate the molar mass of CH₃COONH₄?

Add up the atomic weights of all the atoms in the formula: 2 × 12.011 + 7 × 1.0080 + 2 × 15.999 + 14.007 = 77.083 g/mol.

How many grams are in 2 moles of CH₃COONH₄?

m = n × M = 2 mol × 77.083 g/mol = 154.166 g.

See Also