Molar Mass of CH3COOC2H5 (Ethyl Acetate)
Molar Mass Calculator
What is the molar mass of CH3COOC2H5?
Answer
M(CH3COOC2H5) =
88.106 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Ccarbon | 4 | 12.011 | 48.044 w ≈ 54.53% | ≈ 54.53% |
| Hhydrogen | 8 | 1.0080 | 8.0640 w ≈ 9.15% | ≈ 9.15% |
| Ooxygen | 2 | 15.999 | 31.998 w ≈ 36.32% | ≈ 36.32% |
| Σ = 88.106 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
C 54.53%O 36.32%
H 9.15%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| Sr (strontium) | 87.62 |
| FeS (iron(II) sulfide) | 87.91 |
| C₃H₄O₃ (pyruvic acid) | 88.062 |
| CH₃COOC₂H₅ (ethyl acetate) | 88.106 |
| C₅H₁₂O (isoamyl alcohol) | 88.150 |
| Y (yttrium) | 88.906 |
| C₃H₇NO₂ (L-alanine) | 89.094 |
FAQ
What is the molar mass of CH3COOC2H5?
M(CH₃COOC₂H₅) = 88.106 g/mol
How to calculate the molar mass of CH₃COOC₂H₅?
Add up the atomic weights of all the atoms in the formula: 4 × 12.011 + 8 × 1.0080 + 2 × 15.999 = 88.106 g/mol.
How many grams are in 2 moles of CH₃COOC₂H₅?
m = n × M = 2 mol × 88.106 g/mol = 176.212 g.
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- Молярная масса CH3COOC2H5 (этилацетат): расчёт
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