Subtraction with Regrouping: 803 − 239

Subtraction with Regrouping Calculator
Minuend
Subtrahend

What is 803 − 239?

Answer

803 − 239 =
564

With regrouping across a zero: 2 borrows — there are no tens to borrow from, so 1 hundred becomes 10 tens, and 1 ten goes to the ones

803 − 239 in a column. Above the columns: the values after borrowing — a crossed-out digit is replaced by the number above it; +10 marks a column that received a borrowed ten.
79+10
8(was 8, now 7)0(was 0, now 9)3 (was 3, now 13)
−239
564

Column by column: 803 − 239

  • Ones: 3 is less than 9 — borrow 1 hundred across the zero: hundreds 8 → 7, tens 0 → 9; 13 − 9 = 4 — write 4.
  • Tens: after borrowing, 9; 9 − 3 = 6 — write 6.
  • Hundreds: after borrowing, 7; 7 − 2 = 5 — write 5.

803 − 239 = 564

Second check: 803 − 564 = 239

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Column subtractions of 239

ExampleDifference
507 − 239268
530 − 239291
546 − 239307
564 − 239325
587 − 239348
593 − 239354
615 − 239376
628 − 239389
641 − 239402
666 − 239427
692 − 239453
707 − 239468
724 − 239485
758 − 239519
775 − 239536
803 − 239564
817 − 239578
841 − 239602
886 − 239647
922 − 239683

FAQ

What is 803 − 239?

803 − 239 = 564

How do you check that 803 − 239 = 564?

Add the difference and the subtrahend: 564 + 239 = 803. Getting the minuend back means the difference is right.

How many times do you borrow in 803 − 239?

2 borrows: each time the top digit was smaller than the one below it, 1 was borrowed from the column on the left.

Why does 0 become 9 when borrowing in 803 − 239?

The zero has nothing to lend, so it first borrows 1 from its left neighbour and becomes 10; then it lends 1 to the column on its right and keeps 9.

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