Subtraction with Regrouping: 603 − 67

Subtraction with Regrouping Calculator
Minuend
Subtrahend

What is 603 − 67?

Answer

603 − 67 =
536

With regrouping across a zero: 2 borrows — there are no tens to borrow from, so 1 hundred becomes 10 tens, and 1 ten goes to the ones

603 − 67 in a column. Above the columns: the values after borrowing — a crossed-out digit is replaced by the number above it; +10 marks a column that received a borrowed ten.
59+10
6(was 6, now 5)0(was 0, now 9)3 (was 3, now 13)
−67
536

Column by column: 603 − 67

  • Ones: 3 is less than 7 — borrow 1 hundred across the zero: hundreds 6 → 5, tens 0 → 9; 13 − 7 = 6 — write 6.
  • Tens: after borrowing, 9; 9 − 6 = 3 — write 3.
  • Hundreds: after borrowing, 5; nothing to subtract — write 5.

603 − 67 = 536

Second check: 603 − 536 = 67

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Column subtractions of 67

ExampleDifference
172 − 67105
200 − 67133
203 − 67136
239 − 67172
270 − 67203
300 − 67233
306 − 67239
335 − 67268
374 − 67307
400 − 67333
415 − 67348
443 − 67376
469 − 67402
500 − 67433
520 − 67453
552 − 67485
600 − 67533
603 − 67536
645 − 67578
714 − 67647

FAQ

What is 603 − 67?

603 − 67 = 536

How do you check that 603 − 67 = 536?

Add the difference and the subtrahend: 536 + 67 = 603. Getting the minuend back means the difference is right.

How many times do you borrow in 603 − 67?

2 borrows: each time the top digit was smaller than the one below it, 1 was borrowed from the column on the left.

Why does 0 become 9 when borrowing in 603 − 67?

The zero has nothing to lend, so it first borrows 1 from its left neighbour and becomes 10; then it lends 1 to the column on its right and keeps 9.

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